## Precalculus (6th Edition) Blitzer

Amplitude $=8$ ; $f=\dfrac{1}{4}$ and Period $=4$
Amplitude, $|A|=|-8|=8$ Given: $\omega =\dfrac{\pi}{2}$ and $f=\dfrac{\omega}{2 \pi}$ So, $f=\dfrac{\omega}{2 \pi}=\dfrac{\dfrac{\pi}{2}}{2 \pi}=\dfrac{1}{4}$ Now, period, $P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{\dfrac{\pi}{2}}=4$ Hence, Amplitude $=8$ ; $f=\dfrac{1}{4}$ and Period $=4$