Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 11


$ a=6.71;A=73.4^{\circ}; B=16.6^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\cos A=\dfrac{2}{7} \implies A=73.4^{\circ}$ So, $ B=90^{\circ}- 73.4^{\circ}=16.6^{\circ}$ and $ a= c\sin A=7 \sin 73.4^{\circ}=6.71$ Thus, $ a=6.71;A=73.4^{\circ}; B=16.6^{\circ}$
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