Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 12


$ a=8.06;A=63.6^{\circ}; B=26.4^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\cos A=\dfrac{4}{9} \implies A=63.6^{\circ}$ So, $ B=90^{\circ}- 63.6^{\circ}=26.4^{\circ}$ and $ a= c\sin A=9 \sin 63.6^{\circ}=8.06$ Thus, $ a=8.06;A=63.6^{\circ}; B=26.4^{\circ}$
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