Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 18

Answer

$ d=-8 \cos \pi t $

Work Step by Step

Amplitude, $ A=-8$ (negative because the object is moving down initially.) Given: $ Period =2$ Now, period, $ P=\dfrac{2 \pi}{\omega} \implies \omega =\dfrac{2 \pi}{2}=\pi $ So, $ d=A \cos \omega t=-8 \cos \pi t $
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