Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 2


$ a=17.70; c=26.71; B=48.5^{\circ}$

Work Step by Step

Here, we have $ A=41.5^{\circ}$ ; $ b= 20$ Since, $\tan \theta= \dfrac{Opposite}{Adjacent}$ $ a=20 \tan 41.5^{\circ} =17.70$ Now, $ c=\dfrac{b}{\cos A}=\dfrac{20}{\cos 41.5^{\circ}}=26.71$ So, $ B=90^{\circ} -41.5^{\circ}=48.5^{\circ}$ Thus, $ a=17.70; c=26.71; B=48.5^{\circ}$
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