## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 637: 28

#### Answer

Amplitude $=4$ ; $f=\dfrac{3}{4}$ and Period $=\dfrac{4}{3}$

#### Work Step by Step

Amplitude, $|A|=|-4|=4$ Given: $\omega =\dfrac{3 \pi}{2}$ So, $f=\dfrac{\omega}{2 \pi}=\dfrac{3\pi/2}{2 \pi}=\dfrac{3}{4}$ Now, period, $P=\dfrac{2 \pi}{\omega}=\dfrac{2 \pi}{3\pi/2}=\dfrac{4}{3}$ Hence, Amplitude $=4$ ; $f=\dfrac{3}{4}$ and Period $=\dfrac{4}{3}$

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