Answer
Solution set = $\{e\}$
Work Step by Step
$\ln(\ln x)=0$
$\ln(\ln x)=\ln 1\qquad $ ... log is one-to-one...
$\ln x=1$
$ x=e $
Solution set = $\{e\}$
Check graphically:
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 491: 148
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