Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 491: 148


Solution set = $\{e\}$

Work Step by Step

$\ln(\ln x)=0$ $\ln(\ln x)=\ln 1\qquad $ ... log is one-to-one... $\ln x=1$ $ x=e $ Solution set = $\{e\}$ Check graphically:
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