Answer
True.
Work Step by Step
$ x=\displaystyle \frac{1}{k}\ln y\qquad $ ... $/\times k $
$ kx=\ln y\qquad $ ... $/e^{(...)}$
$ e^{kx}=y $
True.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 491: 143
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