Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 491: 135

Answer

$ t\approx 7.9$ minutes

Work Step by Step

Graphing, the solution is at $ t\approx 7.9$ minutes. (see below) Algebraically, $ 70=145e^{-0.092t}\qquad $ ... $/\div 145$ $\displaystyle \frac{70}{145}=e^{-0.092t}\qquad $... $/\ln(...)$ $\displaystyle \ln(\frac{70}{145})=-0.092t\qquad $... $/\div(-0.092)$ $ t=\displaystyle \frac{\ln(70/145)}{-0.092}\approx 7.915635873$ $ t\approx 7.9$ minutes
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.