## Precalculus (6th Edition) Blitzer

The statement is false. To make it true, replace "$e^{2}=x+3$" with "$10^{2}=x+3$".
The logarithm (written without a base) is the common logarithm, and its base is 10. By definition of logarithms ( $y=\log_{b}x \Leftrightarrow x=b^{y}$), $\log(x+3)=2$ means $10^{2}=x+3.$