## Precalculus (6th Edition) Blitzer

The statement is false. To make it true, replace the last equation with $10^{4}=\displaystyle \frac{7x+3}{2x-5}$
No. Before writing in exponential form, the LHS must be written as one logarithm. This is achieved by applying the quotient rule: $\displaystyle \log\frac{7x+3}{2x-5}=4$ Now we write this in exponential form using $y=\log_{b}x \Leftrightarrow x=b^{y}$, $10^{4}=\displaystyle \frac{7x+3}{2x-5}$