Answer
Does not make sense.
Work Step by Step
No.
To solve the first equation, you would use the definition of logarithms:
if $ y=\log_{b}x $ then $ x=b^{y}$)
The next step would be
$ 3x+1=10^{5}\qquad $, etc.
The second equation is solved by applying the one-to-one property of logarithmic functions:
if $\log_{b}M=\log_{b}N,$ then $ M=N $
So the next step is
$ 3x+1=5\qquad $, etc.
