Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 28

Answer

quotient $x^6-2x^5+5x^4-10x^3+10x^2-20x+40$ and remainder $r(x)=\frac{-68}{x+2}$
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Work Step by Step

Step 1. The coefficients of the dividend can be identified in order as $\{1,0,1,0,1,0,0,12\}$ and the divisor is $x+2$; use synthetic division as shown in the figure to get the quotient and the remainder. Step 2. We can identify the result as $\frac{x^7+x^5-10x^3+12}{x+2}=x^6-2x^5+5x^4-10x^3+10x^2-20x+40+\frac{-68}{x+2}$ with the quotient as $x^6-2x^5+5x^4-10x^3+10x^2-20x+40$ and the remainder as $r(x)=\frac{-68}{x+2}$
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