Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 12

Answer

quotient $x^3+3x^2+9x+27$ and remainder $r(x)=\frac{0}{x-3}$
1581863823

Work Step by Step

Step 1. Using long division as shown in the figure, we can obtain $\frac{x^4-81}{x-3}=x^3+3x^2+9x+27+\frac{0}{x-3}$ Step 2. We can identify the quotient as $x^3+3x^2+9x+27$ and the remainder as $r(x)=\frac{0}{x-3}$
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