Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 10


quotient $3x+7$ and remainder $r(x)=\frac{26}{x-3}$

Work Step by Step

Step 1. Using long division as shown in the figure, we can obtain $\frac{3x^2-2x+5}{x-3}=3x+7+\frac{26}{x-3}$ Step 2. We can identify the quotient as $3x+7$ and the remainder as $r(x)=\frac{26}{x-3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.