## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 19

#### Answer

quotient $3x-8$ and remainder $r(x)=\frac{20}{x+5}$

#### Work Step by Step

Step 1. The coefficients of the dividend can be identified as $\{3,7,-20 \}$ and the divisor as $x+5$; use synthetic division as shown in the figure to get the quotient and the remainder. Step 2. We can identify the result as $\frac{3x^2+7x-20}{x+5}=3x-8+\frac{20}{x+5}$ with the quotient as $3x-8$ and the remainder as $r(x)=\frac{20}{x+5}$

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