Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 15


quotient $6x^2+3x-1$ and remainder $r(x)=\frac{-3x+1}{3x^2+1}$

Work Step by Step

Step 1. Using long division as shown in the figure, we can obtain $\frac{18x^4+9x^3+3x^2}{3x^2+1}=6x^2+3x-1+\frac{-3x+1}{3x^2+1}$ Step 2. We can identify the quotient as $6x^2+3x-1$ and the remainder as $r(x)=\frac{-3x+1}{3x^2+1}$
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