Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 5

Answer

quotient $2x^2+3x+5$ and remainder $r(x)=0$
1581817815

Work Step by Step

Step 1. Using long division as shown in the figure, we can obtain $\frac{6x^3+7x^2+12x-5}{3x-1}=2x^2+3x+5+\frac{0}{3x-1}$ Step 2. We can identify the quotient as $2x^2+3x+5$ and the remainder as $r(x)=0$
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