Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 363: 14

Answer

quotient $x^2+x-3$ and remainder $r(x)=\frac{-12}{x^2+x-2}$
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Work Step by Step

Step 1. Using long division as shown in the figure, we can obtain $\frac{x^4+2x^3-4x^2-5x-6}{x^2+x-2}=x^2+x-3+\frac{-12}{x^2+x-2}$ Step 2. We can identify the quotient as $x^2+x-3$ and the remainder as $r(x)=\frac{-12}{x^2+x-2}$
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