Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 1

Answer

5,8,11,14

Work Step by Step

To find the first four terms of the sequence whose general term is $a_{n}$ = 3n+2, we replace n in the formula with 1,2,3, and 4. n=1, $a_{1}$ = 3*1+2 = 3+2=5 n=2, $a_{2}$ = 3*2+2 = 6+2= 8 n=3, $a_{3}$ = 3*3+2 = 9+2 = 11 n=4,$a_{4}$ = 3*4+2 = 12+2 =14 The first four terms are 5,8,11 and 14.
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