#### Answer

3,9,27, 81

#### Work Step by Step

To ﬁnd the first four terms of the sequence whose general term is $a_{n}$ = $3^{n}$, we replace n in the formula with 1,2,3, and 4.
n=1, $a_{1}$ = $3^{1}$ = 3
n=2, $a_{2}$ = $3^{2}$ = 3*3 = 9
n=3, $a_{3}$ = $3^{3}$ = 3*3*3 = 27
n=4,$a_{4}$ = $3^{4}$ = 3*3*3*3 = 81
The ﬁrst four terms are 3,9,27 and 81.