Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 3

Answer

3,9,27, 81

Work Step by Step

To find the first four terms of the sequence whose general term is $a_{n}$ = $3^{n}$, we replace n in the formula with 1,2,3, and 4. n=1, $a_{1}$ = $3^{1}$ = 3 n=2, $a_{2}$ = $3^{2}$ = 3*3 = 9 n=3, $a_{3}$ = $3^{3}$ = 3*3*3 = 27 n=4,$a_{4}$ = $3^{4}$ = 3*3*3*3 = 81 The first four terms are 3,9,27 and 81.
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