Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set: 22

Answer

-2,-2,-4,-12

Work Step by Step

To find the first four terms of the sequence whose general term is $a_{n}$ = -2(n-1)!, we replace n in the formula with 1,2,3, and 4. n=1, $a_{1}$ = -2(1-1)! = -2*0! = -2*1 =-2 n=2, $a_{2}$ =-2(2-1)! = -2*1! = -2*1 = -2 n=3, $a_{3}$ = -2(3-1)! = -2*2! = -2*2*1 = -4 n=4,$a_{4}$ = -2(4-1)! = -2*3! = -2*3*2*1 = -12 The first four terms are -2,-2,-4,-12.
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