#### Answer

-2,-2,-4,-12

#### Work Step by Step

To ﬁnd the first four terms of the sequence whose general term is $a_{n}$ = -2(n-1)!, we replace n in the formula with 1,2,3, and 4.
n=1, $a_{1}$ = -2(1-1)! = -2*0! = -2*1 =-2
n=2, $a_{2}$ =-2(2-1)! = -2*1! = -2*1 = -2
n=3, $a_{3}$ = -2(3-1)! = -2*2! = -2*2*1 = -4
n=4,$a_{4}$ = -2(4-1)! = -2*3! = -2*3*2*1 = -12
The ﬁrst four terms are -2,-2,-4,-12.