#### Answer

3,7,11,15

#### Work Step by Step

To ﬁnd the first four terms of the sequence whose general term is $a_{n}$ = 4n-1, we replace n in the formula with 1,2,3, and 4.
n=1, $a_{1}$ = 4*1 - 1 = 4-1=3
n=2, $a_{2}$ = 4*2 - 1 = 8 -1= 7
n=3, $a_{3}$ = 4*3 - 1 = 12 - 1 = 11
n=4,$a_{4}$ = 4*4 -1 = 16 - 1=15
The ﬁrst four terms are 3,7,11, and 15.