Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 25

Answer

120

Work Step by Step

$\frac{16!}{2! 14!}$ Try to reduce the fraction before performing the multiplications. We can express 16! as 16! = 16*15*14!. We can divide both the numerator and the denominator by the common factor, 14!. $\frac{16!}{2! 14!}$ = $\frac{ 16*15*14!}{2*1*14!}$ = $\frac{16*15}{2}$= 120
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