#### Answer

2n+1

#### Work Step by Step

$\frac{(2n+1)!}{2n!}$
Try to reduce the fraction before performing the multiplications.
We can express (2n+1)! as
(2n+1)! = (2n+1) 2n!.
We can divide both the numerator and the denominator by the common factor, 2n!.
$\frac{(2n+1)!}{2n!}$= $\frac{ (2n+1)2n!}{2n!}$ = 2n+1