Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 28



Work Step by Step

$\frac{(2n+1)!}{2n!}$ Try to reduce the fraction before performing the multiplications. We can express (2n+1)! as (2n+1)! = (2n+1) 2n!. We can divide both the numerator and the denominator by the common factor, 2n!. $\frac{(2n+1)!}{2n!}$= $\frac{ (2n+1)2n!}{2n!}$ = 2n+1
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