Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set: 27

Answer

(n+2)(n+1)

Work Step by Step

$\frac{(n+2)!}{n!}$ Try to reduce the fraction before performing the multiplications. We can express (n+2)! as (n+2)! = (n+2)(n+1) n!. We can divide both the numerator and the denominator by the common factor, n!. $\frac{(n+2)!}{n!}$ = $\frac{ (n+2)(n+1) n!}{n!}$ = (n+2)(n+1)
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