#### Answer

(n+2)(n+1)

#### Work Step by Step

$\frac{(n+2)!}{n!}$
Try to reduce the fraction before performing the multiplications.
We can express (n+2)! as
(n+2)! = (n+2)(n+1) n!.
We can divide both the numerator and the denominator by the common factor, n!.
$\frac{(n+2)!}{n!}$ = $\frac{ (n+2)(n+1) n!}{n!}$ = (n+2)(n+1)