## Precalculus (6th Edition) Blitzer

$\frac{(n+2)!}{n!}$ Try to reduce the fraction before performing the multiplications. We can express (n+2)! as (n+2)! = (n+2)(n+1) n!. We can divide both the numerator and the denominator by the common factor, n!. $\frac{(n+2)!}{n!}$ = $\frac{ (n+2)(n+1) n!}{n!}$ = (n+2)(n+1)