Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 9



Work Step by Step

we have $a_1=-2 $ and $d=2$ For an arithmetic sequence, we have $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Now, $S_{50}=\dfrac{50}{2}(2(-2)+(50-1)2)$ or, $=25(-4+98)$ Thus, $S_{50}=2350$
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