Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 17



Work Step by Step

Given: $\dfrac{1}{3}+\dfrac{2}{4}+\dfrac{3}{5}+...+\dfrac{18}{20}$ we can see that the consecutive numbers for numerators starts and lasts from $1$ to $18$ and the consecutive numbers for denominators starts and lasts from number $3$ to $20$. This means that the numbers must be shown by a summation symbol as written as: $\dfrac{1}{3}+\dfrac{2}{4}+\dfrac{3}{5}+...+\dfrac{18}{20}=\sum_{i=1}^{18}\dfrac{i}{i+2}$
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