Answer
$-29300$
Work Step by Step
we have $a_1=4 $ and $d=-6$
For an arithmetic sequence, we have $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$
Now, $S_{100}=\dfrac{100}{2}(2(4)+(100-1)(-6))$
or,$=50(8+(-594))$
Thus, $S_{100}=-29300$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Mid-Chapter Check Point - Page 1077: 11
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