Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 5



Work Step by Step

we have $a_1=2 $ and $d=4$ Now, $a_n=a_1+(n-1)d$ Thus, $a_n=2+(n-1)d$ and $a_{20}=2+(20-1)4=2+(19)(4)=78$
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