Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 1


First five terms: $1,-2,\dfrac{3}{2},\dfrac{-2}{3},\dfrac{5}{24}$

Work Step by Step

First five four of $a_n=\dfrac{(-1)^{n+1}n}{(n-1)!}$ are listed as below: $a_1=\dfrac{(-1)^{1+1}}{(1-1)!}=1$; $a_2=\dfrac{(-1)^{2+1}(2)}{(2-1)!}=-2$; $a_3=\dfrac{(-1)^{3+1}(3)}{(3-1)!}=\dfrac{3}{2}$ ; $a_4=\dfrac{(-1)^{4+1}(4)}{(4-1)!}=\dfrac{-4}{6}=\dfrac{-2}{3}$; $a_5=\dfrac{(-1)^{5+1}(5)}{(5-1)!}=\dfrac{5}{24}$ First five terms: $1,-2,\dfrac{3}{2},\dfrac{-2}{3},\dfrac{5}{24}$
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