# Chapter 10 - Mid-Chapter Check Point - Page 1077: 1

First five terms: $1,-2,\dfrac{3}{2},\dfrac{-2}{3},\dfrac{5}{24}$

#### Work Step by Step

First five four of $a_n=\dfrac{(-1)^{n+1}n}{(n-1)!}$ are listed as below: $a_1=\dfrac{(-1)^{1+1}}{(1-1)!}=1$; $a_2=\dfrac{(-1)^{2+1}(2)}{(2-1)!}=-2$; $a_3=\dfrac{(-1)^{3+1}(3)}{(3-1)!}=\dfrac{3}{2}$ ; $a_4=\dfrac{(-1)^{4+1}(4)}{(4-1)!}=\dfrac{-4}{6}=\dfrac{-2}{3}$; $a_5=\dfrac{(-1)^{5+1}(5)}{(5-1)!}=\dfrac{5}{24}$ First five terms: $1,-2,\dfrac{3}{2},\dfrac{-2}{3},\dfrac{5}{24}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.