Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 2


First five terms: $5,2,-1,-4,-7$

Work Step by Step

Since, $a_n=a_1+(n-1)d$ we have $a_1=5 $ and $d=-3$ Therefore, $a_2=a_1+d=5-3=2$; $a_3=a_2+d=2-3=-1$ $a_4=a_3+d=-1-3=-4$ $a_5=a_4+d=-4-3=-7$ First five terms: $5,2,-1,-4,-7$
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