Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 13



Work Step by Step

As we are given that $\sum_{i=1}^{50}(3i-2)$ Now, terms will be {$1,4,7,10,...,148$}; this implies that it shows an arithmetic sequence. whose sum will be $S_{50}=\dfrac{n}{2}(a_1+a_n)=\dfrac{50}{2}(1+148)=25(149)$ Finally, $S_{50}=3725$
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