Answer
$3,1,3,1,3$
Work Step by Step
Given $a_1=3, a_n=-a_{n-1}+4$, we have:
$a_1=3$
$a_2=-a_{1}+4=-3+4=1$
$a_3=-a_{2}+4=-1+4=3$
$a_4=-a_{3}+4=-3+4=1$
$a_5=-a_{4}+4=-1+4=3$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Mid-Chapter Check Point - Page 1077: 4
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