Answer
See below.
Work Step by Step
$LHS=ln|tan\theta|=ln|\frac{sin\theta}{cos\theta}|=ln\frac{|sin\theta|}{|cos\theta|}=ln|sin\theta|-ln|cos\theta|=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 98
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