Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 87

Answer

See below.

Work Step by Step

$LHS=\frac{(cos^2\theta-sin^2\theta)^2}{(cos^2\theta+sin^2\theta)(cos^2\theta-sin^2\theta)}=\frac{cos^2\theta-sin^2\theta}{cos^2\theta+sin^2\theta}=cos^2\theta-sin^2\theta=1-2sin^2\theta=RHS$
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