Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 101

Answer

See below.

Work Step by Step

Step 1. $f(x)=sin(x)\cdot \frac{sin(x)}{cos(x)}=\frac{sin^2(x)}{cos(x)}$ Step 2. $g(x)=\frac{1}{cos(x)}-cos(x)=\frac{1-cos^2(x)}{cos(x)}=\frac{sin^2(x)}{cos(x)}=f(x)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.