Answer
See below.
Work Step by Step
$LHS=\frac{sin^2\theta+sin\theta cos\theta -sin\theta cos\theta+cos^2\theta}{sin\theta cos\theta}=\frac{1}{sin\theta cos\theta}=sec\theta csc\theta=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 81
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