Answer
See below.
Work Step by Step
$LHS=\frac{sec^2(v)-2sec(v) tan(v)+tan^2(v)+1}{csc(v)(sec(v)-tan(v))}=\frac{2sec(v)(sec(v)-tan(v))}{csc(v)(sec(v)-tan(v))}=\frac{2/cos(v)}{1/sin(v)}=2tan(v)=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 79
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