Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 84

Answer

See below.

Work Step by Step

$LHS=\frac{(sin\theta+cos\theta)(sin^2\theta-sin\theta cos\theta+cos^2\theta)}{sin^2\theta-cos^2\theta}=\frac{1-sin\theta cos\theta}{sin\theta-cos\theta}=\frac{1/cos\theta-sin\theta}{sin\theta/cos\theta-1}=\frac{sec\theta-sin\theta}{tan\theta-1}=RHS$
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