Answer
See below.
Work Step by Step
$LHS=\frac{1+sin\theta}{1-sin\theta}\times\frac{1+sin\theta}{1-sin\theta}=\frac{(1+sin\theta)^2}{1-sin^2\theta}=(\frac{1+sin\theta}{cos\theta})^2=(sec\theta+tan\theta)^2=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 78
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