Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 97

Answer

See below.

Work Step by Step

$LHS=ln|sec\theta|=ln|\frac{1}{cos\theta}|=-ln|cos\theta|=RHS$
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