Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 102

Answer

See below.

Work Step by Step

Step 1. $f(x)=cos(x)\frac{cos(x)}{sin(x)}=\frac{cos^2(x)}{sin(x)}$ Step 2. $g(x)=\frac{1}{sin(x)}-sin(x)=\frac{1-sin^2(x)}{sin(x)}=\frac{cos^2(x)}{sin(x)}=f(x)$
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