Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 458: 56



Work Step by Step

Note that $\cot {x}=\frac{1}{\tan{(x)}}$. Hence, $\cot^{-1}{x}=\tan^{-1} {\left(\frac{1}{x}\right)}$. Use a calculator in radian mode and round the result to decimal places to obtain $\cot^{-1}{(-\sqrt{10})}=\tan^{-1} {\left(\dfrac{1}{-\sqrt{10}}\right)}\approx-0.31$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.