Answer
$\frac{2\pi}{3}$
Work Step by Step
Step 1. Evaluate $sin(\frac{7\pi}{6})=-sin(\frac{\pi}{6})=-\frac{1}{2}$
Step 2. Evaluate $cos^{-1}(-\frac{1}{2})=\frac{2\pi}{3}$
Step 3. We have $cos^{-1}(sin(\frac{7\pi}{6}))=\frac{2\pi}{3}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 458: 36
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