Answer
$-0.42$
Work Step by Step
Note that $\cot {x}=\frac{1}{\tan{(x)}}$.
Hence, $\cot^{-1}{x}=\tan^{-1} {\left(\frac{1}{x}\right)}$.
Use a calculator in radian mode and round the result to decimal places to obtain
$\cot^{-1}{(-\sqrt5)}=\tan^{-1} \left({\frac{1}{-\sqrt5}}\right)\approx-0.42$