Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 458: 43



Work Step by Step

$\cot^{-1}{-\frac{\sqrt3}{3}}=\frac{2\pi}{3}$, because $\cot{\frac{2\pi}{3}}=-\frac{\sqrt3}{3}$ and $\frac{2\pi}{3}$ is in the range of $\cot^{-1}{x}$, which is $(0,\pi).$
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