Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 458: 44

Answer

$-\frac{\pi}{3}$

Work Step by Step

$\csc^{-1}{-\frac{2\sqrt3}{3}}=-\frac{\pi}{3}$, because $\csc{-\frac{\pi}{3}}=-\frac{2\sqrt3}{3}$ and $-\frac{\pi}{3}$ is in the range of $\csc^{-1}{x}$, which is $[-\frac{\pi}{2},\frac{\pi}{2}]$ \ $\left\{0\right\}.$
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