Answer
$2$
Work Step by Step
Note that $\cos^{-1}{\left(\dfrac{1}{2}\right)}=\dfrac{\pi}{3}$, because $\cos{\left(\dfrac{\pi}{3}\right)}=\dfrac{1}{2}$ and $\dfrac{\pi}{3}$ is in the range of $\cos^{-1}{x}$, which is $\left[0,\pi\right].$
Thus
$\sec{\left(\cos^{-1}{\left(\dfrac{1}{2}\right)}\right)}=\sec{\left(\dfrac{\pi}{3}\right)}=2.$