Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.2 The Inverse Trigonometric Functions (Continued) - 7.2 Assess Your Understanding - Page 458: 35

Answer

$-\frac{\pi}{4}$

Work Step by Step

Step 1. Evaluate $cos(\frac{3\pi}{4})=-cos(\frac{\pi}{4})=-\frac{\sqrt 2}{2}$ Step 2. Evaluate $sin^{-1}(-\frac{\sqrt 2}{2})=-\frac{\pi}{4}$ Step 3. We have $sin^{-1}(cos(\frac{3\pi}{4}))=-\frac{\pi}{4}$
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